Kayana

joined 5 months ago
[–] [email protected] 11 points 3 weeks ago (3 children)

Can you even kill something that's already dead?

[–] [email protected] 2 points 1 month ago* (last edited 1 month ago)

But you just completely ignored everything I said in that comment.

Mathematically, that is precisely how O notation works, only (as I've mentioned) we don't use it like that to get meaningful results. Plus, when looking at time, we can actually use O notation like normal, since computers can indeed calculate something for infinity.

Still, you're wrong saying that isn't how it works in general, which is really easy to see if you look at the actual definition of O(g(n)).

Oh, and your computer crashing is a thing that could happen, sure, but that actually isn't taken into account for runtime analysis, because it only happens with a certain chance. If it would happen after precisely three days every time, then you'd be correct and all algorithms would indeed have an upper bound for time too. However it doesn't, so we can't define that upper bound as there will always be calculations breaking it.

[–] [email protected] 6 points 1 month ago (2 children)

It's very pedantic, but he does have a point. Similar to how you could view memory usage as O(1) regardless of the algorithm used, just because a computer doesn't have infinite memory, so it's always got an upper bound on that.

Only that's not helpful at all when comparing algorithms, so we disregard that quirk and assume we're working with infinite memory.

[–] [email protected] 0 points 1 month ago

That may be true for smaller cities, but in bigger cities it becomes impossible, because there just isn't enough space to house all the people near areas of interest. Cars don't factor in there at all. Give me a subway for the major areas, and perhaps a tram or bus system so you don't need that many subway stations in the residential areas, and you can have car-free city centers.

[–] [email protected] 2 points 1 month ago* (last edited 1 month ago)

To be honest, I don't really like it either, which might surprise you considering my last sentence. I just couldn't resist making a small pun myself.

[–] [email protected] 1 points 1 month ago (1 children)

Got a laugh from me, but I did mean only the 'a', not the 'ar'. I couldn't think of any other English word with that sound unfortunately, do you have a better suggestion?

[–] [email protected] 27 points 1 month ago (7 children)

I don't really like including pedestrians in there. Like sure, you can fit a bunch of people in a small area, but another point you shouldn't ignore is the throughput over time, and pedestrians are by their nature rather slow. Obviously if you're looking at shopping in a street lined by shops left and right, then that street becomes tailor-made for pedestrian traffic (and nothing else except perhaps bicycles). But public transport is much better suited for travelling any further distances, and that should be the main focus when deciding to ditch cars.

[–] [email protected] 1 points 1 month ago (8 children)

Try pronouncing the 'a' in pan like the 'a' in large, then you'll end up with a rather well-done pun.

[–] [email protected] 2 points 1 month ago

Late reply, but for me personally, I started doing it because my Keepass database is already accessed using two factors (password and key file). Therefore, I'd gain very little by keeping the second factor of those sites external - essentially, those second factors are compounded into the second factor for the database.

[–] [email protected] 26 points 2 months ago

Funnily enough, in D&D 5E that wizard explicitly can cast that spell (if you're equating Power Word Kill to Avada Kedavra)

[–] [email protected] 1 points 2 months ago* (last edited 2 months ago) (1 children)

I mean, it's literally the second sentence in that article: Dragon Rider by Cornelia Funke

[–] [email protected] 0 points 2 months ago (1 children)

Wouldn't 10d10 be something very different? Like, I can get a result of 43 with the commonly used definition of 10d10 (10 dice with 10 sides each), but I can only get multiples of 10 with the die in question.

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